Asked by jojo
solve for equation x(give answer in radians using exact values only.
2sin(x)+cot(x)-csc(x)=0
2sin(x)+cot(x)-csc(x)=0
Answers
Answered by
Steve
putting everything i nterms of sin and cos, you have
2sinx + cosx/sinx - 1/sinx = 0
(2sin^2 x + cosx - 1)/sinx = 0
so, x where sinx=0 must be excluded from the domain.
(2 - 2cos^2 x + cosx - 1) = 0
2cos^2 x - cosx - 1 = 0
(2cosx + 1)(cosx - 1) = 0
so, you need
cosx = -1/2 or cosx = 1
2sinx + cosx/sinx - 1/sinx = 0
(2sin^2 x + cosx - 1)/sinx = 0
so, x where sinx=0 must be excluded from the domain.
(2 - 2cos^2 x + cosx - 1) = 0
2cos^2 x - cosx - 1 = 0
(2cosx + 1)(cosx - 1) = 0
so, you need
cosx = -1/2 or cosx = 1
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