Asked by Becky
A ball is moving at 82 m/s when it hits a ball at rest which has a mass fours times as big as its own. The formally stationary ball leaves the collision with a speed of 7.5 m/s what is the final velocity of the first ball?
Answers
Answered by
Elena
The law of conservation of linear momentum for elastic collision
m1•v1 = m1•u1 + m2•v2.
The velocities after collision are
u1 =(m1-m2) •v1/(m1+m2)
u2 =2•m1•v1/(m1+m2)
Since m2=4m1,
u1 =(m -4m) •82/(m+4m) = - 49.2 m/s
u2 =2•m •82/(m +4m) = 32.8 m/s
m1•v1 = m1•u1 + m2•v2.
The velocities after collision are
u1 =(m1-m2) •v1/(m1+m2)
u2 =2•m1•v1/(m1+m2)
Since m2=4m1,
u1 =(m -4m) •82/(m+4m) = - 49.2 m/s
u2 =2•m •82/(m +4m) = 32.8 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.