Asked by Cali
A ball moving at +3.0 m/s along a table rolls off a table and lands on the ground 2.0 m away. How high was the table?
Answers
Answered by
Damon
How long was it in the air?
It went 2 meters at 3 m/s
t = 2m/(3m/s) = 2/3 seconds
d = (1/2) a t^2 = -4.9 t^2
d = -4.9(4/9)
= -2.18
It fell 2.18 meters (high table )
It went 2 meters at 3 m/s
t = 2m/(3m/s) = 2/3 seconds
d = (1/2) a t^2 = -4.9 t^2
d = -4.9(4/9)
= -2.18
It fell 2.18 meters (high table )
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