A 0.02 kg ball moving to the right at 0.25 m/s makes an elastic head-on collision with a 0.04 kg ball moving to the left at 0.15 m/s. After the collision, the smaller ball moves to the left at 0.16 m/s. What is the velocity of the 0.04 kg ball after collision?

M1*V1 + M2*V2 = M1*V3 + M2*V4

0.02*0.25 - 0.04*0.15 = 0.02*(-0.16) + 0.04*V4
0.005-0.006 = - 0.0032 + 0.04*V4
-0.001 + 0.0032 = 0.04*V4
0.04*V4 = 0.0022
V4 = 0.055 m/s.

Vam

A 0.02 kg ball moving to the right at 0.25 m/s makes an elastic head-on collision with a 0.04 kg ball moving to the left at 0.15 m/s. After the collision, the smaller ball moves to the left at 0.16 m/s. What is the velocity of the 0.04 kg ball after collision?

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Putangina ng physics

Sebutir peluru 20 gram bergerak dengan kecepatan 10 ms−1 arah mendatar menumbuk balok bermassa 60 gram yang sedang diam di atas lantai. Jika peluru tertahan di dalam balok, maka kecepatan balok sekarang adalah

To find the velocity of the 0.04 kg ball after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision, provided that there are no external forces acting on the system.

The formula for momentum is:

momentum = mass × velocity

For the 0.02 kg ball moving to the right, the initial momentum is:

momentum1 = (0.02 kg) × (0.25 m/s) = 0.005 kg·m/s (to the right)

For the 0.04 kg ball moving to the left, the initial momentum is:

momentum2 = (0.04 kg) × (-0.15 m/s) = -0.006 kg·m/s (to the left)

Since this is an elastic collision, the total momentum before the collision is:

total momentum before collision = momentum1 + momentum2
= 0.005 kg·m/s - 0.006 kg·m/s
= -0.001 kg·m/s

The total momentum after the collision is equal to the sum of the momentum of each ball after the collision. Let's assume the velocity of the 0.04 kg ball after the collision is v.

For the 0.02 kg ball after the collision, the momentum is:

momentum1' = (0.02 kg) × (-0.16 m/s) = -0.0032 kg·m/s (to the left)

For the 0.04 kg ball after the collision, the momentum is:

momentum2' = (0.04 kg) × v

The total momentum after the collision is:

total momentum after collision = momentum1' + momentum2'

Using the conservation of momentum principle, we can equate the total momentum before the collision to the total momentum after the collision:

-0.001 kg·m/s = -0.0032 kg·m/s + (0.04 kg) × v

Solving this equation, we can find the velocity of the 0.04 kg ball after the collision.