Asked by jose
a 69.3g sample of oxalic ac acid, H2C2O4, was dissolved in 1.000L of solution. How would yo prepare 1.00L of 0.150M H2C2O4 from this solution?
Answers
Answered by
bobpursley
figure moles in 69.3g.
moles: 69.3/90=you do it.
Molarity of original solution: 69.3/90=.77M
So you want to decrease molarity to .150, you do that by diluting with water.
You want to dilute it .77/.150 times, or 5.13 times, which means 4.13 parts water, and 1 part original solution.
making one liter, you need each part to be 1000ml/5.13=195ml
Take 195 ml of the original solution, and add water to the 1 liter mark, stir, label, and properly store.
check my figuring.
moles: 69.3/90=you do it.
Molarity of original solution: 69.3/90=.77M
So you want to decrease molarity to .150, you do that by diluting with water.
You want to dilute it .77/.150 times, or 5.13 times, which means 4.13 parts water, and 1 part original solution.
making one liter, you need each part to be 1000ml/5.13=195ml
Take 195 ml of the original solution, and add water to the 1 liter mark, stir, label, and properly store.
check my figuring.