Asked by Ivy
A 19.18 mL of 0.125 M Oxalic Acid (H2C2O42H2O) is titrated with a Ca (OH)2
solution. The initial volume of Ca(OH)2 was 14.38 and the final volume of
Ca(OH)2 was 28.29 mL when the solution turned very slightly pink. What is the
concentration of Ca (OH)2?
solution. The initial volume of Ca(OH)2 was 14.38 and the final volume of
Ca(OH)2 was 28.29 mL when the solution turned very slightly pink. What is the
concentration of Ca (OH)2?
Answers
Answered by
DrBob222
H2Ox + Ca(OH)2 ==> CaOx + 2H2O
moles H2Ox = M x L = ??
moles Ca(OH)2 = same as H2Ox because the equation shows the reaction is 1:1.
Then M Ca(OH)2 = mols/L
You know, of course, to find the volume of Ca(OH)2 that you subtract the final volume from the initial volume.
moles H2Ox = M x L = ??
moles Ca(OH)2 = same as H2Ox because the equation shows the reaction is 1:1.
Then M Ca(OH)2 = mols/L
You know, of course, to find the volume of Ca(OH)2 that you subtract the final volume from the initial volume.
Answered by
Ivy
Why is it H2Ox instead of H2C2O4?