Asked by lou
calculate the mass of oxalic acid dihydrate C2H2O4.2H2O required to react with 30 ml of 0.20 M sodium hydroxide solution?
Answers
Answered by
DrBob222
H2C2O4.2H2O + 2NaOH ==> Na2C2O4 + 4H2O
moles NaOH = M x L = 0.20 M x 0.030 L = ??
moles H2C2O4.2H2O required = moles NaOH x 1/2
mass H2C2O4.2H2O = moles x molar mass.
Post your work if you get stuck. Check my work.
moles NaOH = M x L = 0.20 M x 0.030 L = ??
moles H2C2O4.2H2O required = moles NaOH x 1/2
mass H2C2O4.2H2O = moles x molar mass.
Post your work if you get stuck. Check my work.
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