Question

Calculate the oxalic acid mass required for neutralization of 25 ML of 0.1 M NaOH solution.Dihydrate Organic Diacid (H2C2O4.2 H2O, molar mass = 126.04 g/mol)
H2ox = the oxalic acid dihydrate

H2ox + 2NaOH ==> Na2ox + 2H2O
millimols NaOH = mL x M = 25 x 0.1 = 2.5
You will need 1/2 that or 1.25 millimols H2ox = 0.00125 mols.
grams H2ox = mols H2ox x molar mass H2Ox = ?

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