Question

A 25kg crate is sitting at the bottom of an inclined plane. The inclined plane 12m long meets the horizontal at an angle of 15 degrees and has a coefficient of friction of 0.55. A force is applied to the crate so as to slide the crate up the incline at a constant speed.

What is the magnitude of the force F required to push the sled up the incline at a constant speed?
(194N)

Answer 1

force= ma+component of weight mg perpendiuclar x coefficent

force= m*0 + mg*mu*CosTheta