Asked by James T.

A 25kg box is pulled across a frictionless floor by a rope that is inclined 30 degrees above horizontal. The tension in the rope is 50N. How much work is done by the force in moving the crate 10 meters? If the box started at rest, what is the final velocity of the box?
Answered by Henry
a. Work = Fx * d = 50*Cos30 * 10 = 433 J

Answered by test
test
Answered by Mark Kabwe
A 50Kg box slid across the floor at a constant velocity of 20m/s, with a 45N force acting at 40o with respect to the horizontal. The coefficient of kinetic friction between the box and the surface is 0.3. Find,
a) The frictional force acting on the box.
b) The normal force
c) The acceleration of the box in 25s
d) Distance covered in 30s
e) The kinetic energy
f) The work done.
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