Asked by ryan
a box with a mass of 25kg is lifted (without acceleration) through a height of 2.0m, in order to place it upon the shelf of a closet. The value of acceleration due to gravity g= 9.8ms^2
How much work is required to lift the box to this position? i figured out the potential energy and i got 490J PE=mgh but how do i figure out the work. w=f X d
How much work is required to lift the box to this position? i figured out the potential energy and i got 490J PE=mgh but how do i figure out the work. w=f X d
Answers
Answered by
bobpursley
the work must equal the PE gained by the box.
Answered by
ryan
so would it look like this 490= f x 2.0
245J ??
245J ??
Answered by
bobpursley
PEgained=m*g*height=25kg*9.8N/kg*2m
that is not 245J.
If you insist on f x d, the force is weight: 25*9.8=you do it N
and d is 2 m
again, work is equal to the PE gained.
that is not 245J.
If you insist on f x d, the force is weight: 25*9.8=you do it N
and d is 2 m
again, work is equal to the PE gained.
Answered by
ryan
122.5J ? when your saying work is equal to the PE gained. does that mean its 490j??
Answered by
ryan
i got it bob thanks lol should be 490J!!
Answered by
Anindya Kanti Sen
PE=mgh
Work done against gravity =mgh
PE=Work Done
Work done against gravity =mgh
PE=Work Done
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