Asked by Samarth

Find work done when 25kg weight lifted to a vertical height of 2m from the ground carrying to the same place by pushing it up and inclined plane make the angle of 30 degree (g=9.8)
Answered by Henry
Work = F * d = Mg * d = 25*9.8 * 2 = 490 J.

sin30 = 2/L. L = 4 m. = Length of incline.

Fp = Mg*sin30 = 25*9.8*sin30 = 122.5 N. = Force in parallel with
the incline.

Work = Fp*L = 122.5 * 4 = 490 J.

Answered by Akanksha
Why we multiply w.d with length of the incline
Answered by sonali maurya
explain 2 part of the answer
Answered by Chaudhary ayush _ gurjar
Explain second point
Answered by Rajesh mishra
Explane your answer
Answered by Shruti
Why you multiplied by 4 when displacement is 2 m
Answered by Prasoon
Right
Answered by Shivam Giri
Why u multiply by 4 😭
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