Asked by julie
I'm trying to find the weight of a lemon.
Weight of container= 48 g
Container + pure lemon juice = 184 g (100 ml)
Pure lemon juice= 184g-48= 136g
Does this make sense? Because I thought lemon had around the same density to water... wouldn't that mean my answer should be closer to 100?
Weight of container= 48 g
Container + pure lemon juice = 184 g (100 ml)
Pure lemon juice= 184g-48= 136g
Does this make sense? Because I thought lemon had around the same density to water... wouldn't that mean my answer should be closer to 100?
Answers
Answered by
DrBob222
And think you are right. I think the density of pure lemon juice is fairly close to that of water. Perhaps the lemon juice you used has seeds? or pulp? I think 1.36 g/mL sounds high to me. In answer to your last question no, it means the answer should be closer to 1.0 g/mL. Or yes, the mass of the 100 mL should be closer to 100 g.
Answered by
DrBob222
I see from another post that you are asking about the weight. I also note you seem to be using the weight of a lemon and the pure lemon juice almost interchangeably. You know, of course, they are not the same.
Did you weigh the whole lemon? That's not pure lemon juice.
Did you use a good pair of scales and did you read the numbers right?
Did you weigh the whole lemon? That's not pure lemon juice.
Did you use a good pair of scales and did you read the numbers right?
Answered by
julie
I juiced the lemons again and got 50 ml and 140g. 8% of citric acid
mol C6H8O7 = 140g x (1 mol/192.14g)
192.14 is the molar mass of C6H8O7
= .7286 mol
c= n/v
.7286 mol/.050 L
=14.57 M
%8 C6H8O7 = 14.57 M x .08
= 1.166 M
I needed to find 8% of citric acid so I just pretended 100% was citric acid and found 8% of it.
V= 50 ml x .08 = 4 mL
citric acid volume/total volume of cleaner
v/v%= 4 mL/500 ml x100
= .8%
Pretty sure this is what I'm supposed to do
mol C6H8O7 = 140g x (1 mol/192.14g)
192.14 is the molar mass of C6H8O7
= .7286 mol
c= n/v
.7286 mol/.050 L
=14.57 M
%8 C6H8O7 = 14.57 M x .08
= 1.166 M
I needed to find 8% of citric acid so I just pretended 100% was citric acid and found 8% of it.
V= 50 ml x .08 = 4 mL
citric acid volume/total volume of cleaner
v/v%= 4 mL/500 ml x100
= .8%
Pretty sure this is what I'm supposed to do
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