Asked by Abdul Waheed

A worker pushes 25Kg crate a distance of 5m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic frication between the crate and the floor is 0.23.
(a) What magnitude of force must the worker apply?
(b) How much work is done on the crate by this force?
(c) How much work is done on the crate by frication?
(d) How much work is done on the crate by normal force?
(e) How much work is done on the crate by the gravity?
(f) What is the total work done on the crate?
Answered by drwls
(a) The applied force must equal the friction force. You should know how to calculate that, using the friction coefficient.
(b) Force x (5 m)
(c) minus (b) answer
(d) zero
(e) zero
(f) zero
Answered by Eduardo
The answer above is very stupid
Answered by Eduardo's mom
Don't talk like that. Apologize right now or you're grounded
Answered by Eduardo's Dad
yeah what she said. No video games for a month!
Answered by drwls, SJW worker
way to go man, because if I didn't know the equations, your snarkiness will show me the light.
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