Question

a worker pushes a box with a horizontal force of 50 N over a level distance of 5m. If a frictional force of 43 N acts on the box in a direction opposite to that of the worker, what was the net work done to the box?
35J
Work = (force) x (distance)

The worker does (50N) x (5m) = 250 joules of work.

Friction eats up (43N) x (5m) = 215 joules of that energy,
generating 215 joules of heat.

The remaining (250J - 215J) = 35 joules of energy moves the box.

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