Question

The worker pushes with a force of 10 N that points downward at an angle of 45° below the horizontal. What component of the force moves the crate forward?

I do not know how to set up this problem, so any help would be appreciated.

Answer 1

the component of the force that moves the crate (horizontal) is...the applied force, multiplied by the sine of the angle to the component

10N * sin(45º)