Asked by Anonymous
A worker pushes a wheelbarrow with a force of 40 N over a level distance of 6.0 m. If a frictional force of 24 N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?
Answers
Answered by
bobpursley
worker work=40*6=240j
frictionwork:24*6=144j
net work= difference.
frictionwork:24*6=144j
net work= difference.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.