Asked by Lee
Evaluate
integral sign (x-1/(2x))^2 dx=
integral sign (x-1/(2x))^2 dx=
Answers
Answered by
Steve
(x - 1/(2x))^2 = x^2 - 1 + 1/(4x)
((x-1)/(2x))^2 = (x^2 - 2x + 1)/(4x^2) = 1/4 - 1/(2x) + 1/(4x^2)
Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy.
((x-1)/(2x))^2 = (x^2 - 2x + 1)/(4x^2) = 1/4 - 1/(2x) + 1/(4x^2)
Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy.
Answered by
Steve
oops. Top one should end with 1/(4x^2)
Answered by
Lee
Thanks
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