Asked by Cynthia
to evaluate (integral) 3x^2 cos (2x^3-4) dx, it is necessary to let
A. u=3x^2
B. u=6x
C. u=2x^3-4
D. u=6x^2
A. u=3x^2
B. u=6x
C. u=2x^3-4
D. u=6x^2
Answers
Answered by
Steve
C
then du = 2(3x^2) dx
then du = 2(3x^2) dx
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