Ask a New Question

Question

to evaluate (integral) 3x^2 cos (2x^3-4) dx, it is necessary to let

A. u=3x^2
B. u=6x
C. u=2x^3-4
D. u=6x^2
13 years ago

Answers

Steve
C

then du = 2(3x^2) dx
13 years ago

Related Questions

how do you evaluate integral of [lxl] from (0,2) , a step function. would you just do it as if it... Evaluate the integral using method of integration by parts: (integral sign)(e^(2x))sin(5x)dx How do I evaluate this integral: x^9cos(x^5)dx Hint: First make a substitution and then use inte... Evaluate the integral: sin^2(5x)cos^2(5x)dx how do i evaluate the integral of secxdx how do i evaluate the integral of dx/ x^2 +9 how to i evaluate the integral of dx/ (x^2 +9) with a u substitution of x/3? Can someone show thi... Evaluate the integral of (((ln(x))^7)/x)dx evaluate the integral using integration by parts 7xe^-x Evaluate this integral (1+2m)^2 ----------------- dm √m
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use