Question

Evaluate the integral.

The integral from the square root of three over three to the square root of three of the function 6/(t^2+1)

Answer 1

This is one of your standard integrals:

∫dx/(x^2+1) = arctan(x)

now, what angle θ has tanθ = √3/3?
θ = pi/6

Now go and crank on it. If you get stuck, come on back.