Another standard:
∫dx/√(1-x^2) = arcsin(x)
sin pi/4 = √2/2
Crank thou onward . . .
Evaluate the integral.
The integral from 0 to the square root of 2 over 2 of the function 8/sq. rt.(1-t^2)
1 answer
The integral from 0 to the square root of 2 over 2 of the function 8/sq. rt.(1-t^2)
1 answer
1 answer
1 answer
1 answer
1 answer