Asked by Amy
Find an equation in slope-intercept form passing through the (2,5) and (7, -3).
Answers
Answered by
Steve
since you have two points, you can get the slope:
(-3-5)/(7-2) = -8/5
Now, the slope never changes, so, you can pick any other point (x,y) on the line, and figure the slope through (2,5) and (x,y) the same way:
(y-5)/(x-2) = -8/5
Now just rearrange things the way you want.
y-5 = -8/5 (x-2)
y-5 = -8/5 x + 16/5
y = -8/5 x + 41/5
(-3-5)/(7-2) = -8/5
Now, the slope never changes, so, you can pick any other point (x,y) on the line, and figure the slope through (2,5) and (x,y) the same way:
(y-5)/(x-2) = -8/5
Now just rearrange things the way you want.
y-5 = -8/5 (x-2)
y-5 = -8/5 x + 16/5
y = -8/5 x + 41/5
Answered by
Kayla
Juan says, "When you put together unequal groups, you can only add." Is he correct? Explain.
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