Asked by bianca
Find an equation in slope-intercept form passing through the points (2,5) and (7,-3).
M=(-3,-5)/(7,-2)
M=-8/5 IS THE SLOPE
[Y=MX+B]
5=-8/5*2+B
5=-16/5+B
5+16/5=B
(25+16)/5=B
41/5=B THE Y INTERCEPT
Y=-8X/5 +41/5
HOW WOULD I SHOW A GRAPH ON THIS PROBLEM?
M=(-3,-5)/(7,-2)
M=-8/5 IS THE SLOPE
[Y=MX+B]
5=-8/5*2+B
5=-16/5+B
5+16/5=B
(25+16)/5=B
41/5=B THE Y INTERCEPT
Y=-8X/5 +41/5
HOW WOULD I SHOW A GRAPH ON THIS PROBLEM?
Answers
Answered by
Reiny
your slope is incorrect
slope = (-2+5)/(7+3) = 3/10
so y = (3/10)x + b
using (-3,-5)
-5 = (3/10)(-3) + b
-50 = -9 + 10b
b = -41/10
y = (3/10)x - 41/10
slope = (-2+5)/(7+3) = 3/10
so y = (3/10)x + b
using (-3,-5)
-5 = (3/10)(-3) + b
-50 = -9 + 10b
b = -41/10
y = (3/10)x - 41/10
Answered by
Helper
http://www.purplemath.com/modules/graphlin.htm
I'm not sure of your question.
Do you know how to graph an equation?
Is it because there are fractions?
If because of fractions, convert to decimals and estimate as best you can.
Your equation would be,
y = -1.6 x + 8.2
I'm not sure of your question.
Do you know how to graph an equation?
Is it because there are fractions?
If because of fractions, convert to decimals and estimate as best you can.
Your equation would be,
y = -1.6 x + 8.2
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