Asked by Taylor95
Find te equation in slope-intercept form of the line that is the perpendicular bisector of the segment between (-3,4) and (3,-8).
Answers
Answered by
bobpursley
find the midpoint ((-3+3)/2, (4-8)/2)
I think that is 0,-2 check it.
now find the slope: changey/changex
slope= 4+8 / -3-3= 12/-6=-2
perpendicular slope= 1/2 (negative reciprocal).
So the question now is find the equation of the line with slope 1/2, and has the point 0,-2 in it
y=mx+b
put in m, y, and x, solve for b, and you have the line
y=mx + b
I think that is 0,-2 check it.
now find the slope: changey/changex
slope= 4+8 / -3-3= 12/-6=-2
perpendicular slope= 1/2 (negative reciprocal).
So the question now is find the equation of the line with slope 1/2, and has the point 0,-2 in it
y=mx+b
put in m, y, and x, solve for b, and you have the line
y=mx + b
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.