Asked by Lindsey
In the winter sport of curling, players give a 20 kg stone a push across a sheet of ice. A curler accelerates a stone to a speed of 3.0 m/s over a time of 2 s.
a)How much force does the curler exert on the stone?
b)What average power does the curler use to bring the stone up to speed?
a)How much force does the curler exert on the stone?
b)What average power does the curler use to bring the stone up to speed?
Answers
Answered by
drwls
The acceleration rate while pushing is 3.0/2 = 1.5 m/s^2
The force required to accelerate the stone at that rate is F = M*a = 30 N.
This assumes zero ice friction resistance. That is a fairly good assumption, since they travel so far.
Average power = (kinetic energy added)/(2 seconds)
= (M/2)Vfinal^2/Time = 45 watts
The force required to accelerate the stone at that rate is F = M*a = 30 N.
This assumes zero ice friction resistance. That is a fairly good assumption, since they travel so far.
Average power = (kinetic energy added)/(2 seconds)
= (M/2)Vfinal^2/Time = 45 watts
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