Asked by Sarah
A curling stone with a mass of 18 kg slides 38m across a sheet of ice in 8.0 s before it stops because of friction. What is the co¨efficient of kinetic friction between the ice and the stone? (Note: you will need to calculate the acceleration of the stone first.)
I solved for acceleration by dividing the distance by time for velocity and then again for acceleration. I think this isn't right though as my coefficient is 0.06 when the answer is 0.12.
I solved for acceleration by dividing the distance by time for velocity and then again for acceleration. I think this isn't right though as my coefficient is 0.06 when the answer is 0.12.
Answers
Answered by
Damon
your AVERAGE velocity = 38/8 = 4.75
That means at the start your velocity is twice that
Vi = 2*4.75 = 9.5 m/s
and at finsh v = 0
SO
a = -9.5/8 = -1.1875 m/s^2
so F = m a = - 21.375 Newtons
m g = 18*9.81 = 176.58 Newtons
mu = 21.375 / 176.58 = 0.121
That means at the start your velocity is twice that
Vi = 2*4.75 = 9.5 m/s
and at finsh v = 0
SO
a = -9.5/8 = -1.1875 m/s^2
so F = m a = - 21.375 Newtons
m g = 18*9.81 = 176.58 Newtons
mu = 21.375 / 176.58 = 0.121
Answered by
Jason
I'd say your right. lol
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