Asked by Jennie
A curling stone is moving at a velocity of 8 m/s stops after sliding 5 m across a surface that has 70 N of friction. What is the stone’s mass?
Answers
Answered by
R_scott
work to stop ... 5 m * 70 N = 350 Joules
... this equals the initial K.E.
K.E. = 1/2 m v^2
350 = 1/2 * m * 8^2 ... m is in kg
... this equals the initial K.E.
K.E. = 1/2 m v^2
350 = 1/2 * m * 8^2 ... m is in kg
Answered by
henry2,
V^2 = Vo^2 + 2a*d = 0
8^2 + 2a*5 = 0
a = -6.4 m/s^2.
Mg = M*9.8 = Wt. of stone.
M*9.8 - 70 = M*a
9.8M-70 = -6.4M
16.2M = 70
M = 4.3 kg.
8^2 + 2a*5 = 0
a = -6.4 m/s^2.
Mg = M*9.8 = Wt. of stone.
M*9.8 - 70 = M*a
9.8M-70 = -6.4M
16.2M = 70
M = 4.3 kg.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.