Question
a curling rock with a mass 22 kg is traveling 0 degrees at 3m/s and collides with a stationary object with the same mass the collision is a glancing one and the struck roce is moving 1m/s at 65 degrees what is the velocity after the collision
Answers
bobpursley
The final momentum is 22*3 kg m/s
you are given one objects mass, velocity after collision.
for that object, zero deg momentum is 22*1*cos65
subtract that from the initial momentum at zero, and you have the zero deg momentum of rock 2.
Now the other direction>
at 90 deg, the moving rock momentum is 22*1*sin65
the other rock must be moving then at momentum 22^1*sin(180+65)
now, you can find the velocity and direction of the original rock after collision, you have two components at ninety degrees.
you are given one objects mass, velocity after collision.
for that object, zero deg momentum is 22*1*cos65
subtract that from the initial momentum at zero, and you have the zero deg momentum of rock 2.
Now the other direction>
at 90 deg, the moving rock momentum is 22*1*sin65
the other rock must be moving then at momentum 22^1*sin(180+65)
now, you can find the velocity and direction of the original rock after collision, you have two components at ninety degrees.