Asked by Brittney
Suppose a 19.3 kg curling stone was on a frictionless ramp. If the ramp is 4.76 m tall and 19.5 m long (along the incline), how much mass must hang from the pulley in order that the stone not accelerate up or down the ramp?
Answers
Answered by
Henry
Ws = m*g = 19.3kg * 9.8N/kg = 189 N. =
Wt. of stone.
sinA = Y/r = 4.76 / 19.5 = 0.2441
A = 14.1 Deg.
Fs = 189N @ 14.1 Deg. = Force of stone.
Fp = 189*sin14.1 = 46 N. = Force parallel to ramp. = Force to hang on
pulley.
m*g = 46
m*9.8 = 46
m = 4.7 kg = Mass on the pulley.
Wt. of stone.
sinA = Y/r = 4.76 / 19.5 = 0.2441
A = 14.1 Deg.
Fs = 189N @ 14.1 Deg. = Force of stone.
Fp = 189*sin14.1 = 46 N. = Force parallel to ramp. = Force to hang on
pulley.
m*g = 46
m*9.8 = 46
m = 4.7 kg = Mass on the pulley.
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