Asked by Jancy
(sec theta + cosec theta) (sin theta +cos theta) = 2 + sec theta cosec theta
Answers
Answered by
Reiny
LS = secØsinØ + secØcosØ + cscØsinØ + cscØcosØ
= secØsinØ + 1 + 1 + cscØcosØ , since both secØcosØ and cscØsinØ are equal to 1
= 2 + secØsinØ + cscØcosØ
= RS
= secØsinØ + 1 + 1 + cscØcosØ , since both secØcosØ and cscØsinØ are equal to 1
= 2 + secØsinØ + cscØcosØ
= RS
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