Asked by George
A solution is prepared by dissolving 130 g of NaNO3 in 100 g of water at 80°C. The solution is cooled to 0°C. How many grams of compound remain in solution?
How many grams of solid are formed?
How many grams of solid are formed?
Answers
Answered by
bobpursley
This is pretty easy. WAht is the saturated level (mass NaOH3 per 100gwater). Look at the solubility curves to get that.
http://www.goldrecovery.us/images/solgraph.jpg
Then, that point tells you how much is still in solution.
The difference is how much precipated.
http://www.goldrecovery.us/images/solgraph.jpg
Then, that point tells you how much is still in solution.
The difference is how much precipated.
Answered by
Pob
do i find out what the saturated level is for 80C or 0C
Answered by
Yosef
The molarity of urea in a solution prepared by dissolving 16 g of urea (MW = 60.0 g/mol) in 39g of H2O is M. The density of the .solution is 1.3 g/mL 0.11 .a O 6.3 .b O 3.7 .C O 6.8 .d o 0.16 .e O