Asked by Tammy
A solution is prepared by dissolving 10.0 moles of Na2SO4 solid in 0.500 kg H2O. what is the vapor pressure of the solution at 30 C?
Answers
Answered by
GK
*10 moles of Na2SO4 is 3*10=30 moles of particles.
*Convert 0.500 kg H2O to moles.
*Total moles = 30 + moles of H2O
*Mole fraction of H2O = X(H2O) = (moles H2O) / Total moles.
*Look up the vapor pressure of H2O at 30ºC = P(H2O)
*Vapor pressure of solution = [X(H2O)]*[P(H2O)]
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