23.7/molar mass CaCl2 = moles CaCl2
moles Cl^- = 2 times that.
Convert 3675 g water to liters using the density. Then M = mols/L.
A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting
solution is 1.05 g/mL. The concentration of Cl- in this solution is __________ M.
can someone help me? how do i get to M?
2 answers
1.12?
1 answer