Asked by BenY

A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting
solution is 1.05 g/mL. The concentration of Cl- in this solution is __________ M.

can someone help me? how do i get to M?
Answered by DrBob222
23.7/molar mass CaCl2 = moles CaCl2
moles Cl^- = 2 times that.
Convert 3675 g water to liters using the density. Then M = mols/L.
Answered by Osaid
1.12?
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