A solution is prepared by dissolving 0.5842g of oxalic acid (H2C2O4) in enough water to make 100.0ml of solution. A 10.00ml aliquot (portion) of this solution is then diluted to a final volume of 250.0ml. What is the final molarity of thus prepared oxalic acid solution?

Answer 1

moles H2C2O4 = grams/molar mass
moles x (10/100) = moles in 250 mL.
M = moles/0.250 = ??

Answer 2

The final answer is 10000 ????