Asked by NONO

A solution is prepared by dissolving 0.5842g of oxalic acid (H2C2O4) in enough water to make 100.0ml of solution. A 10.00ml aliquot (portion) of this solution is then diluted to a final volume of 250.0ml. What is the final molarity of thus prepared oxalic acid solution?
Answered by DrBob222
moles H2C2O4 = grams/molar mass
moles x (10/100) = moles in 250 mL.
M = moles/0.250 = ??
Answered by NONO
The final answer is 10000 ????
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