A solution is prepared by dissolving 150 g of CH4N2O into 4.5 L of solution. What is the molarity of this solution?

Answer 1

To find the molarity of the solution, we first need to calculate the number of moles of CH4N2O in 150 g.

The molar mass of CH4N2O (urea) is:
Carbon: 12.01 g/mol
Hydrogen: 1.008 g/mol
Nitrogen: 14.01 g/mol
Oxygen: 16.00 g/mol

Adding these up, we get:
12.01 + 4(1.008) + 14.01 + 16.00 = 60.07 g/mol

Now, we can calculate the number of moles of CH4N2O in 150 g:
Number of moles = mass / molar mass
Number of moles = 150 g / 60.07 g/mol
Number of moles ≈ 2.497 moles

Now, we can calculate the molarity of the solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 2.497 moles / 4.5 L
Molarity ≈ 0.554 M

Therefore, the molarity of the solution is approximately 0.554 M.