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Asked by mashitah

A solution is prepared by dissolving 10.00 g of glucose, C6H12O6, in 500 g of water. The
final volume of the solution is 415 mL
i)Determine the moles of glucose, C6H12O6
ii)Calculate the molality of the solution
4 years ago

Answers

Answered by DrBob222
molar mass C6H12O6 = 180
mols glucose = grams/molar mass = 10.00/180 = ?
molality = mols glucose/kg solvent = mols glucose/0.500 = ?
4 years ago
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