Asked by mashitah
A solution is prepared by dissolving 10.00 g of glucose, C6H12O6, in 500 g of water. The
final volume of the solution is 415 mL
i)Determine the moles of glucose, C6H12O6
ii)Calculate the molality of the solution
final volume of the solution is 415 mL
i)Determine the moles of glucose, C6H12O6
ii)Calculate the molality of the solution
Answers
Answered by
DrBob222
molar mass C6H12O6 = 180
mols glucose = grams/molar mass = 10.00/180 = ?
molality = mols glucose/kg solvent = mols glucose/0.500 = ?
mols glucose = grams/molar mass = 10.00/180 = ?
molality = mols glucose/kg solvent = mols glucose/0.500 = ?
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