Asked by hye
differentiate b) g(x) = (8x^2 - 3x)^3
Answers
Answered by
MathMate
g(x) = (8x^2 - 3x)^3 = u^3
use the chain rule:
d(g(x))/dx
= d(u^3)/du * du/dx
=3u^2*du/dx
=3(8x^2-3x)²*(16x-3)
use the chain rule:
d(g(x))/dx
= d(u^3)/du * du/dx
=3u^2*du/dx
=3(8x^2-3x)²*(16x-3)
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