Question

Differentiate

g(x)=(x^3+1)(3x^2-1)

so I use g'(x) X h(x) + g(x) X h'(x)

so the derivative of (x^3+1)=3x^2
and (3x^3-1)=6x

So (3x^2)(x^3+1) + (x^3+1)(6x) Is this correct so far. If so this is where I am stuck. I am having trouble simplifing.

Answer 1

You made a mistake applying the "derivative of a product" formula.

g'(x) = (3x^2)(3x^2-1) + (x^3+1)*6x
= 12x^4 -3x^2 +6x
= 3x(4x^3 -x^2 +2)

Answer 2

Actually I figure it out.

Answer 3

In google type: calc101

When you see list of resultc click on:

Calc101com Automatic Calculus and Algebra Help

When page be open clik option: derivatives

When this page be open in rectacangle type:

(x^3+1)(3x^2-1)

and click options DO IT

You will see solution step-by-step

By the way on this site you can practice any kind of derivation.

Answer 4

Thank You!!