Asked by Dan
The equilibrium constant for the reaction of bromine and chlorine to form bromine chloride under certain conditions is 4.7x10-2.
Cl2(g) + Br2(g) --> 2BrCl(g) K= 4.7 x 10-2
What is the equilibrium constant for the following reaction under the same conditions?
1/2 Cl2(g) + 1/2 Br2(g) --> BrCl(g) K=?
Thanks.
Cl2(g) + Br2(g) --> 2BrCl(g) K= 4.7 x 10-2
What is the equilibrium constant for the following reaction under the same conditions?
1/2 Cl2(g) + 1/2 Br2(g) --> BrCl(g) K=?
Thanks.
Answers
Answered by
bobpursley
k= [BrCl]^2 / [Cl2][Br2]
in the second reaction,
k'= [BrCl2]/[ Cl2]^.5 [Br2]^.5= sqrt k
check my reasoning.
in the second reaction,
k'= [BrCl2]/[ Cl2]^.5 [Br2]^.5= sqrt k
check my reasoning.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.