Asked by Lily

The equilibrium constant Kc^i is 3.2x10^-34 at 25 degrees C for 2HCl(g) -> H2(g) + Cl2 (g). The equilibrium constant Kc^ii is .10 at 25 degrees C for 2ICl (g) -> Cl2 (g) + I2 (g).

a) Calculate the equilibrium constant Kc for the reaction below at 25 C
Cl2(g) + I2 (g) -> 2ICl (g)

Answers

Answered by DrBob222
This must be a multipart question sincer the Kc data for HCl is not relevant.
You have 2ICl ==> I2 + Cl2 and you want the reverse of that. Just take the reciprocal of Kc for the forward rxn or
Kc reverse = 1/Kc forward
Answered by joe
mama
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