Asked by alex

given the equilibrium constant for the following reaction at 500 K,
2 NO (g) + O2 (g) <==> 2 NO2 (g) Kc = 6.2x10^5
calculate the equilibrium constant for the reaction expressed as partial pressures, Kp.

the answer is 1.51x10^4. How do i get this?
Answered by DrBob222
Kp = Kc(RT)<sup>delta n</sup>
delta n = nproducts-nreactants.
Answered by Anonymous
hhk
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