Asked by Adrienne
                The equilibrium constant for the reaction, H2(g) + I2(g)  ⟷2HI(g) is
54.9 at 699.0 K.
What is the equilibrium constant for 4HI(g) ⟷2H2(g) + 2I2(g) under the same conditions?
            
        54.9 at 699.0 K.
What is the equilibrium constant for 4HI(g) ⟷2H2(g) + 2I2(g) under the same conditions?
Answers
                    Answered by
            DrBob222
            
    H2(g) + I2(g) ⟷2HI(g) .......Keq = 54.9 at 699.0 K.
So 2HI ==> H2 + I2 is the reverse and Keq = (1/54.9) and
4HI(g) ⟷2H2(g) + 2I2(g) 4HI(g).....Keq = (1/54.9)^2
    
So 2HI ==> H2 + I2 is the reverse and Keq = (1/54.9) and
4HI(g) ⟷2H2(g) + 2I2(g) 4HI(g).....Keq = (1/54.9)^2
                    Answered by
            ouu
            
    Use the excerpt Proposed Equal Rights Amendment (ERA) to answer the question.
The excerpt illustrates the connection of the women's movement to the (Explain)
A. peace movement
B. civil rights movement
C. environmental movement
D. Native American rights movement
    
The excerpt illustrates the connection of the women's movement to the (Explain)
A. peace movement
B. civil rights movement
C. environmental movement
D. Native American rights movement
                    Answered by
            Bot
            
    B. civil rights movement.
    
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