Question
The equilibrium constant for the reaction of the weak base aniline is Kb = 4.3e-10.
C6H5NH2 (aq) + H2O (l) --> C6H5NH3+ (aq) + OH- (aq).
Calculate ΔG at 298 K when [C6H5NH2] = 0.250 M, [C6H5NH3+] = 1.0E-5 M, [OH-] = 0.000480 M
i used the equations dG=dG^o - RTlnQ and
dG^o= -RTlnK
and got the answer 97456.76003, but im told that answer is incorrect...what did i do wrong?
C6H5NH2 (aq) + H2O (l) --> C6H5NH3+ (aq) + OH- (aq).
Calculate ΔG at 298 K when [C6H5NH2] = 0.250 M, [C6H5NH3+] = 1.0E-5 M, [OH-] = 0.000480 M
i used the equations dG=dG^o - RTlnQ and
dG^o= -RTlnK
and got the answer 97456.76003, but im told that answer is incorrect...what did i do wrong?
Answers
Isn't dG = dGo + RTlnQ?
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