I think you are missing the boat.
Kp for 2NO + O2 ==> 2NO2 Kp = 1.48E3
You want Kp for
2NO2 ==> 2NO which is just the reverse of the original equation. For that the new Kp = 1/old Kp (i.e., just the reciprocal of old Kp).
I know the equation is Kp=Kc(RT)x Delta n
Kp is what we're solving for
Kc= I can't seem to find.
R=.0821
T=184+273
Delta n= 1
I was wondering if I had set this up right and where I go from here because I'm stuck at this point.
Kp for 2NO + O2 ==> 2NO2 Kp = 1.48E3
You want Kp for
2NO2 ==> 2NO which is just the reverse of the original equation. For that the new Kp = 1/old Kp (i.e., just the reciprocal of old Kp).
Delta n represents the change in the number of moles of gas molecules between the products and the reactants. In this case, we have:
2NO(g) + O2(g) <--> 2NO2(g)
So, on the reactant side, we have 2 moles of NO and 1 mole of O2, giving a total of 3 moles of gas molecules. On the product side, we have 2 moles of NO2, giving a total of 2 moles of gas molecules.
Therefore, the change in the number of moles of gas molecules (delta n) is 2 - 3 = -1.
Now, using the equation Kp = Kc(RT)^delta n, with R = 0.0821 and T = 184 + 273 = 457 K, we can plug in the values:
Kp = Kc(0.0821 * 457)^(-1)
Unfortunately, we still need the value of Kc to proceed further. However, we don't have that information available.
If you can provide the value of Kc, I would be happy to help you calculate Kp. Otherwise, I'm afraid we cannot proceed without that missing piece of information.
Kp = Kc(RT)^(Δn)
Let's break it down step by step:
1. Given that Kp = 1.48x10^4, R = 0.0821 (atm⋅L/mol⋅K), T = 184°C (which is equivalent to 457 K), and Δn = 1.
2. First, we need to find the value of Kc using the equation:
Kp = Kc(RT)^(Δn)
We will rearrange the equation to solve for Kc:
Kc = Kp / (RT)^(Δn)
Substituting the known values:
Kc = (1.48x10^4) / ((0.0821)(457))^1
Kc ≈ 0.1849
3. Now that we have the value of Kc, we can calculate Kp using the equation:
Kp = Kc(RT)^(Δn)
Substituting the known values:
Kp = (0.1849) * ((0.0821)(457))^1
Kp ≈ 0.1849 * 1.188 = 0.2196 (rounded to four significant figures)
Therefore, the calculated value of Kp for the reaction 2NO2(g) <--> 2NO(g) + O2(g) is approximately 0.2196.