Asked by abe

Given the equilibrium constant values:

N2 + 1/2O2 >>> N2O ; kc = 2.7 * 10^-18

N2O4>>>>2NO2 kc=4.6*10^-3

1/2N2 + O2>>>NO2 kc = 4.1 * 10^-9

What is a value of Kc for this reaction?

2N2O + 3O2 >>> 2N2O4

Answered by abe
i got 2.72 * 10^17, and got it wrong. i reversed the first by taking the reciprocal, and reversed the 2nd one, times 2 by the last one. added them, square rooted and then doubled. what did i do wrong
Answered by DrBob222
equation 1 x 2 and reverse. (1/K<sub>1</sub><sup>2</sup>)
equation 2 x 2 and reverse. (1/K<sub>2</sub><sup>2</sup>)
equation 3 x 4 as written. (K<sub>3</sub><sup>4</sup> )

K<sub>c</sub> = (1/K<sub>1</sub><sup>2</sup>)*(1/K<sub>2</sub><sup>2</sup>)*(K<sub>3</sub><sup>4</sup>) = ??

Check my work. Make sure the equations you have added together gets the equation you want at the end. I think this will do it. I've tried to write superscripts and subscripts but if I missed one of the "turn ons or turn offs" it will be messed up. I'll correct it if it appears to be too difficult to decipher.
Answered by Tekilsh
High school teacher
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