Asked by cora
The equilibrium constant for the gas phase
reaction
N2O4 ⇀↽ 2 NO2
at a certain temperature is K = 0.0466. If
the initial concentrations are [N2O4] = 1.0 M,
[NO2] = 0.0 M, what are the final concentrations
of [N2O4] and [NO2], respectively?
1. 1.0 M ; 0.22 M
2. 0.8 M ; 0.2 M
3. 1.2 M ; 0.4 M
4. 0.8 M ; 0.1 M
5. 0.9 M ; 0.2 M
reaction
N2O4 ⇀↽ 2 NO2
at a certain temperature is K = 0.0466. If
the initial concentrations are [N2O4] = 1.0 M,
[NO2] = 0.0 M, what are the final concentrations
of [N2O4] and [NO2], respectively?
1. 1.0 M ; 0.22 M
2. 0.8 M ; 0.2 M
3. 1.2 M ; 0.4 M
4. 0.8 M ; 0.1 M
5. 0.9 M ; 0.2 M
Answers
Answered by
Scott
let [NO₂] equal 2x
(2x)^2 = 0.0466 * (1.0 - x)
4 x^2 + 0.0466 x - 0.0466 = 0
you can use the quadratic formula to find x
but answer 5 is the only one that makes sense
(2x)^2 = 0.0466 * (1.0 - x)
4 x^2 + 0.0466 x - 0.0466 = 0
you can use the quadratic formula to find x
but answer 5 is the only one that makes sense
Answered by
AntiDrBob222
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