Asked by Anonymous

If the equilibrium constant K equals .05, and the reaction C3H8=C3H6 + H2 (all gases), starts with pure C3H8 and is allowed to reach equilibrium at 200 K at a total pressure of 2 bar. Calculate the partial pressure of H2 at equilbirum.
Answered by DrBob222
Is that Kp in bar?
........C3H8 ==> C3H6 + H2


Total P = 2 = pC3H6 + pH2 + pC3H8
Solve for pC3H8 = 2-p-p = 2-2p
Kp = p*p/(2-2p)
Solve for p = H2 = C3H6
Answered by Anonymous
The K is just the equilibrium constant, not Kp. Do you have to convert the K to Kp?
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