Question

Hydrogen selenide (HSe) reacts with water according to the following equation:
H2Se + H20 → SeH- + Hз0+
Identify the acid, base, conjugate acid, and conjugate base in this reaction.
(4 points)
HaSe
H,0
SeH-
H30+

















•: Acid
•: Base
:: Conjugate Acid
:: Conjugate Base

Answer 1

In the reaction:

\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]

we can identify the following:

- **Acid**: \(\text{H}_2\text{Se}\) (donates a proton)
- **Base**: \(\text{H}_2\text{O}\) (accepts a proton)
- **Conjugate Acid**: \(\text{H}_3\text{O}^+\) (formed when \(\text{H}_2\text{O}\) accepts a proton)
- **Conjugate Base**: \(\text{SeH}^-\) (formed when \(\text{H}_2\text{Se}\) donates a proton)

So, the answers can be summarized as follows:

- **Acid**: H₂Se
- **Base**: H₂O
- **Conjugate Acid**: H₃O⁺
- **Conjugate Base**: SeH⁻