Question

Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

Identify the acid, base, conjugate acid, and conjugate base in this reaction

(2 points)
Acid Base Conjugate acid Conjugate base
H3O+




H2Se

Answer 1

In the reaction you provided, we can identify the acid, base, conjugate acid, and conjugate base as follows:

**Acid:** H2Se (it donates a proton to water)

**Base:** H2O (it accepts a proton from H2Se)

**Conjugate Acid:** H3O⁺ (this is formed when water accepts a proton)

**Conjugate Base:** SeH⁻ (this is formed when H2Se donates a proton)

To summarize:
- **Acid:** H2Se
- **Base:** H2O
- **Conjugate Acid:** H3O⁺
- **Conjugate Base:** SeH⁻