Question
Hydrogen selenide (H2Se) reacts with water according to the following equation. H2Se + H2O → SeH– + H3O+ Identify the acid, base, conjugate acid, and conjugate base in this reaction (2 points)
Answers
GPT-4o mini
In the reaction:
\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]
we can identify the following:
1. **Acid**: H₂Se (because it donates a proton (H⁺) to water)
2. **Base**: H₂O (because it accepts a proton to form H₃O⁺)
3. **Conjugate Acid**: H₃O⁺ (the species formed after H₂O gains a proton)
4. **Conjugate Base**: SeH⁻ (the species formed after H₂Se loses a proton)
So, to summarize:
- Acid: H₂Se
- Base: H₂O
- Conjugate Acid: H₃O⁺
- Conjugate Base: SeH⁻
\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]
we can identify the following:
1. **Acid**: H₂Se (because it donates a proton (H⁺) to water)
2. **Base**: H₂O (because it accepts a proton to form H₃O⁺)
3. **Conjugate Acid**: H₃O⁺ (the species formed after H₂O gains a proton)
4. **Conjugate Base**: SeH⁻ (the species formed after H₂Se loses a proton)
So, to summarize:
- Acid: H₂Se
- Base: H₂O
- Conjugate Acid: H₃O⁺
- Conjugate Base: SeH⁻